Shanina Shaik Height, Weight, Body Measurements, Shoe Size, Bio 

 June 10, 2022

Model Shanina Shaik Height, Weight, Body Measurements, Shoe Size, Bio Details. Shanina Shaik is an Australian Model. She was born on 11 February 1991 in Melbourne, Australia. Shanina is the daughter of Hanif Shaik and Kim Shaik. She is Unmarried. She started her professional modeling career in 2008. She appeared in her first Victoria’s Secret Show in 2011.

Shanina Shaik’s height is 5 feet 8 inches around 173 centimeters tall. Her body weight is 51 kilograms around 112 pounds. Her body measurement is 32-23-34 inches. Shanina Shaik’s bra size 32B. Her shoe is size 5 US. Her dress is size 4 US. Her hair color is dark brown. Her eyes color is hazel.

Shanina Shaik

Shanina Shaik Personal Details

  • Complete Name: Shanina Shaik
  • Nicknames: Shanina
  • Date of Birth: February 11, 1991
  • Occupation: Model
  • Birthplace: Melbourne, Australia
  • Zodiac Sign: Aquarius
  • Eye Color: Hazel
  • Hair Color: Dark Brown

Shanina Shaik Body Measurements

Listed below are complete details about model Shanina Shaik’s body measurements including her height, weight, dress, shoe, and bra size.

  • Height: 5′ 8″ (1.73 m)
  • Weight: 51 kg (112 pounds)
  • Bra Size: 32B
  • Shoe Size:5 (US)
  • Dress Size: 4 (US)
  • Body Measurements: 32-23-34

Shanina Shaik Career Highlights

  • Began Professional Modeling: 2008
  • First Victoria’s Secret Show: 2011

Shanina Shaik Facts

  • In 2008, she participated in the reality series Make Me a Supermodel and finished second on the show.
  • She started her modeling career at the age of 8.
  • Shanina Shaik began modeling for Victoria’s Secret in 2011.

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